Current through the sound-sensor: 0
` C_1=frac(C_2R_4)(R_3)`
`R_1=frac(R_3C_4)(C_2)`
There will be some potencial difference across the terminal of the speaker.
Hence, some current will flow through the speaker and it's effect can be heared.
Current through the sound-sensor: 0
`Z_1=R_1-frac(1)(jomegaC_1)`,`Z_2=-frac(1)(jomegaC_2)`
`Z_3=R_3`,
` Z_(1)Z_4=Z_2Z_3`
Now we need to substitute the impedence value's of Schering bridge in the above equation
Then
`(R_1-frac(1)(jomegaC_1))(frac(R_4)(1+jomegaC_4R_4))=(-frac(1)(jomegaC_2))R_3`
Now we need to equate the real and imaginary terms of the above equations
We get,
` C_1=frac(C_2R_4)(R_3)`
`R_1=frac(R_3C_4)(C_2)`
There will be some potencial difference across the terminal of the speaker.
Hence, some current will flow through the speaker and it's effect can be heared.
`R_1` in(Ω) | `C_1` in(μF) | `R_3` in(Ω) | `C_4` in(μF) | `R_4` in(Ω) | `V` in(volt) | `f_r` in(Hz) |
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